Q: I've got the declarations
typedef char *charp; const charp p;Why is p turning out const, instead of the characters pointed to?
A: typedef substitutions are not purely textual. (This is one of the advantages of typedefs; see question 1.13.) In the declaration
const charp p;p is const for the same reason that const int i declares i as const. The typedef'ed declaration of p does not ``look inside'' the typedef to see that there is a pointer involved.
Additional links: further reading
References:
H&S Sec. 4.4.4 pp. 81-2
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